一、简介
Mutex的突出特点是可以跨应用程序域边界对资源进行独占访问,即可以用于同步不同进程中的线程,这种功能当然这是以牺牲更多的系统资源为代价的。.
主要常用的两个方法:
-
public virtual bool WaitOne() 阻止当前线程,直到当前 System.Threading.WaitHandle 收到信号获取互斥锁。
-
public void ReleaseMutex() 释放 System.Threading.Mutex 一次。
二、代码
案例一:
class Program
{
private static Mutex mutex = new Mutex();
static void Main(string[] args)
{
Thread[] thread = new Thread[3];
for (int i = 0; i < 3; i++)
{
thread[i] = new Thread(ThreadMethod1);//方法引用
thread[i].Name = "Thread-" + (i+1).ToString();
}
for (int i = 0; i < 3; i++)
{
thread[i].Start();
}
Console.ReadKey();
}
public static void ThreadMethod1(object val)
{
mutex.WaitOne(); //获取锁
for (int i = 1; i <=5; i++)
{
Console.WriteLine("{0}循環了{1}次", Thread.CurrentThread.Name, i);
}
mutex.ReleaseMutex(); //释放锁
}
}
运行结果:
案例二:
class Program
{
private static Mutex mutex = new Mutex();
private static int sum = 0;
static void Main(string[] args)
{
Task<int> task = new Task<int>(ThreadFunction);
task.Start();
Console.WriteLine($"{DateTime.Now} task started!");
Thread.Sleep(2000);//Main主線程
Console.WriteLine($"{DateTime.Now} Get siginal in Main!");
mutex.WaitOne();
Console.WriteLine($"{DateTime.Now} Get siginal in main!");
Console.WriteLine($"{DateTime.Now} Result is {task.Result}");
Console.ReadKey();
}
private static int ThreadFunction()
{
Console.WriteLine($"{DateTime.Now} Get siginal in ThreadFunction!");
mutex.WaitOne(); //获取锁
for (int i = 0; i <= 10; i++)
{
sum += i;
Thread.Sleep(1000);
}
Console.WriteLine($"{DateTime.Now} Release mutex in ThreadFunction!");
mutex.ReleaseMutex(); //释放锁
return sum;
}
}
运行结果:
三、总结
为避免发送多线程发生死锁,Mutex的WaitOne()和ReleaseMutex()需成对配合使用。